Enter the Liberty’s Big Adventure Sweepstakes for a chance to win a 5-day/4-night trip for four to a state of their choice in the United States!
One Grand prize winner will receive roudntrip airfare for four to their choice state within the United States, for a 5-day/4-night stay, dinner on 1-night, and $2,500 towards incidentals!
In addition, enter for a chance to win a $5,000 shopping spree, or 1 of 30 Liberty Prize Packs worth $70!
ONE (1) GRAND PRIZE; One (1) five (5) day/four (4) night trip (the “trip”) for up to four (4) people to a state of choice within the United States of America. The trip includes round-trip airfare for up to four (4) people from the major airport nearest the grand prize winner’s home (as determined by the Sponsor) to the major airport nearest to the destination of choice within the United States of America (as determined by the Sponsor), limousine airport pickup from the selected airport to the designated hotel, four (4) nights luxury hotel accommodations in one (1) hotel room near the state destination of choice (as determined by the Sponsor), dinner and drink accommodations at a popular restaurant on one (1) night of choice during the trip, and two thousand-five hundred dollar ($2,500.00) credit toward incidentals to be used during the trip. Grand Prize winner will also receive two (2) personally autographed Rush Revere and the Star-Spangled Banner by Rush Limbaugh with Kathryn Limbaugh books (Approximate Retail Value (“ARV”): $21,900.00).
ONE (1) FIRST PRIZE; One (1) five thousand dollar ($5,000.00) cash shopping spree (ARV: $5,000.00).
THIRTY (30) SECOND PRIZES; One (1) Liberty Prize Pack that includes a Rush Revere and the Star-Spangled Banner by Rush Limbaugh with Kathryn Limbaugh book, restaurant gift cards (as determined by the Sponsor) and a Liberty specialized item, (ARV: $70.00 each).